# The car is moving at a speed of 108 km / h with a constant acceleration of 6 m / s2.

The car is moving at a speed of 108  km / h with a constant acceleration of 6 m / s2. Find its braking distance when braking in front of a traffic light in 5 seconds.

V0 = 108 km / h = 30 m / s.

V = 0 m / s.

a = 6 m / s2.

t = 5 s.

S -?

When braking a car with a constant acceleration a, its braking distance S is expressed by the formula: S = V0 * t – a * t2 / 2, where V0 is the speed of the car at the beginning of braking, t is the braking time.

S = 30 m / s * 5 s – 6 m / s2 * (5 s) 2/2 = 75 m.

Answer: when braking in front of a traffic light, the braking distance of the car was S = 75 m.

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