The car moves along a curvature of the road with a radius of 120m, at a speed of 36

The car moves along a curvature of the road with a radius of 120m, at a speed of 36km / h (10m / s). Find the center of the rapid acceleration (A).

R = 120 m.

V = 36 km / h = 10 m / s.

a – ?

With a uniform movement of the car around the circumference, due to a change in the direction of its speed V, the car moves with centripetal acceleration a.

Centripetal acceleration a is determined by the formula: a = V2 / R, where V is the speed of movement, R is the radius of the circle and directed along the radius of the circle to its center.

a = (10 m / s) ^ 2/120 m = 0.83 m / s2.

Answer: the centripetal acceleration of the car when driving on a curved road is a = 0.83 m / s2.