The car moves evenly at a speed of 72 km / h. What work will it do in 10 seconds

The car moves evenly at a speed of 72 km / h. What work will it do in 10 seconds if the traction force of its motor is 2000 N?

V = 72 km / h = 20 m / s.

t = 10 s.

Ftyag = 2000 N.

∠α = 0 °.

A -?

The work of force A is determined by the formula: A = F * S * cosα, where F is the force that acts on the body, S is the movement of the body under the action of the force, ∠α is the angle between the direction of action of the force F and the movement of the body S.

Since the traction force of the machine Ftroot and its movement S are equally directed, then ∠α = 0 °, cos0 ° = 1.

With uniform rectilinear movement, the movement of the body S is expressed by the formula: S = V * t, where V is the speed of movement, t is the time of movement of the machine.

A = Ftyag * V * t.

A = 2000 N * 20 m / s * 10 s = 400000 J.

Answer: the traction force of the machine does the work A = 400,000 J.