The car moves evenly at a speed of 72 km / h. What work will she do in 10 seconds if the thrust

The car moves evenly at a speed of 72 km / h. What work will she do in 10 seconds if the thrust force of her motor is 2000H.

The given tasks: V (speed of uniform movement of the considered machine) = 72 km / h (in the SI system V = 20 m / s); t (running time) = 10 s; F (motor thrust) = 2000 N.

The work that the machine under consideration will perform in 10 s is determined by the formula: A = N * t = F * V * t.

Let’s make a calculation: A = 2000 * 20 * 10 = 400 * 10 ^ 3 J (400 kJ).

Answer: In 10 s, the machine in question will perform work of 400 kJ.