The car moves with constant acceleration a and by the end of the tenth second it reaches a speed of 20 m / s.

The car moves with constant acceleration a and by the end of the tenth second it reaches a speed of 20 m / s. What is the distance traveled by the car in the tenth second? Will this path be greater, equal or less than 20 m?

1) Let’s calculate the constant acceleration of the car:

V = V0 + a * t, where according to the condition V (the speed reached by the car) = 20 m / s; V0 (initial speed) = 0 m / s; t (movement time) = 10 s.

a = V / t = 20/10 = 2 m / s ^ 2.

2) Determine the path of the car in 10 seconds:

S10 = a * t ^ 2/2 = 2 * 10 ^ 2/2 = 100 m.

3) Determine the path of the car in 9 seconds:

S9 = a * t9 ^ 2/2 = 2 * 9 ^ 2/2 = 81 m.

4) Determine the path of the car in the tenth second:

S (10) = S10 – S9 = 100 – 81 = 19 m (less than 20 m).