The car moves with equal slowness, having an initial speed of 54 km / h and an acceleration

The car moves with equal slowness, having an initial speed of 54 km / h and an acceleration of 0.3 m / s ^ 2. How far will the carriage travel to the stop?

These tasks: the movement of the carriage is equally slow; V0 (initial speed of the car) = 54 km / h (in the SI system V0 = 15 m / s); a (acceleration) = 0.3 m / s2.

The distance that the car must travel to the stop is determined by the formula: S = (V0 ^ 2 – V ^ 2) / 2a.

Let’s perform the calculation: S = (15 ^ 2 – V ^ 2) / (2 * 0.3) = 375 m.

Answer: The carriage will pass 375 meters to the stop.