The car, moving evenly at a speed of 72 km / h, covered the same path within 10 seconds

The car, moving evenly at a speed of 72 km / h, covered the same path within 10 seconds as another car covered in 12.5 seconds. What is the speed of the second car?

Initial data: V1 (speed of the first car) = 72 km / h or 20 m / s, t1 (time of movement of the first car) = 10 s, t2 (time of movement of the second car) = 12.5 s, S1 = S2.
1) Decision on action.
S1 = V1 * t1 = 20 * 10 = 200 m.
Since S1 = S2, then V2 * t2 = S1.
V2 = S1 / t2 = 200 / 12.5 = 16 m / s.
2) Solution by proportion:
V1 * t1 = V2 * t2.
V2 = V1 * t1 / t2 = 20 * 10 / 12.5 = 16 m / s.
Answer: The speed of the second car is 16 m / s.