The car, moving with an initial speed of 10 m / s, gained a speed of 18 m / s in 4 s.

The car, moving with an initial speed of 10 m / s, gained a speed of 18 m / s in 4 s. What way did he go during the acceleration?

Initial data: V0 (speed with which the car was moving before acceleration) = 10 m / s; V (vehicle speed after acceleration) = 18 m / s; t (acceleration duration) = 4 s.

1) Let’s calculate the acceleration of the car during acceleration:

V = V0 + a * t.

a = (V – V0) / t = (18 – 10) / 4 = 2 m / s ^ 2.

2) Determine the path of the car during acceleration:

S = V0 * t + a * t ^ 2/2 = 10 * 4 + 2 * 4 ^ 2/2 = 40 + 16 = 56 m.

Answer: During the acceleration, the car covered a distance of 56 meters.