The car passed the second part of the way at double the speed. The average speed of the car along

The car passed the second part of the way at double the speed. The average speed of the car along the entire route was 1.5 times higher than the speed in the first section. Compare the lengths of the first and second sections.

Let the speed in the first section be v, then the speed in the second section is 2v. Let us denote the lengths of the sections of the first and second sections through S1 and S2.

Time to overcome the sections:

t1 = S1 / v

t2 = S2 / 2v

The ratio of the average speed to the speed in the first section:

(S1 + S2) / (t1 + t2) = 1.5v1;

(S1 + S2) / (S1 / v + S2 / 2v) = 1.5v;

S1 + S2 = (S1 / v + S2 / 2v) * 1.5v;

S1 + S2 = 1.5S1 + 0.75S2;

0.25S2 = 0.5S1;

S1 = 0.5S2;

Answer: the first section is half the length of the second section.