The car starts off with an acceleration of 2.4 ms2. What is its movement in 6.5 s? What speed will it pick up during this time?

V0 = 0 m / s.

a = 2.4 m / s2.

t = 6.5 s.

S -?

V -?

Since the car moves uniformly accelerated, then its movement will be expressed by the formula: S = V0 * t + a * t ^ 2 / 2. Since it starts from the place V0 = 0 m / s, the formula for movement will take the form: S = a * t ^ 2/2.

S = 2.4 m / s2 * (6.5 s) ^ 2/2 = 50.7 m.

When driving with constant acceleration a, the vehicle speed is determined by the formula: V = V0 + a * t.

V = a * t.

V = 2.4 m / s2 * 6.5 s = 15.6 m / s.

Answer: the car will move S = 50.7 m and pick up speed V = 15.6 m / s.