The car starts to move and moves with a constant acceleration of 5m / s ^ 2

The car starts to move and moves with a constant acceleration of 5m / s ^ 2 what way did the car go if its speed at the end of the way turned out to be 15m / s.

Initial data: V0 (vehicle speed at the beginning of the path) = 0 m / s, and (constant vehicle acceleration) = 5 m / s2, V (vehicle speed at the end of the path) = 15 m / s.

Formula for calculation:

S = (V2 – V0) / 2a = V ^ 2 / 2a.

Let’s do the calculation:

S = 15 ^ 2 / (2 * 5) = 225/10 = 22.5 m.

Answer: The car covered a distance of 22.5 meters.