The car, the efficiency of which is 25%, consumed 24 kg of gasoline in 3 hours of run.

| May 21, 2021 | education

The car, the efficiency of which is 25%, consumed 24 kg of gasoline in 3 hours of run. The specific heat of combustion of gasoline is 4.6 • 10 ^ 7 J / kg. What is the power of the engine?

To find out the engine power of the presented car, consider the formula: η = Ap / Az = Px * t / (qb * mb), from where we express: Px = η * qb * mb / t.

Const: qb – beats. heat of combustion of gasoline (according to the condition qb = 4.6 * 10 ^ 7 J / kg).

Data: η – motor efficiency (η = 25% = 0.25); mb is the mass of consumed gasoline (mb = 24 kg); t is the duration of the run (t = 3 h = 10800 s).

Let’s perform the calculation: Px = η * qb * mb / t = 0.25 * 4.6 * 10 ^ 7 * 24/10800 = 25.5 (5) * 10 ^ 3 W.

Answer: The engine power of the presented car is 25.5 (5) kW.



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