The car, the mass of which with a load of 20 tons, starts to move with an acceleration of 0.5 m / s2.

The car, the mass of which with a load of 20 tons, starts to move with an acceleration of 0.5 m / s2. Find the traction force if the coefficient of friction is 0.04.

For the solution it is necessary to apply Newton’s second law.

ma = F – Ftr.

Initial data: m (vehicle mass in cargo) = 20 t or 20,000 kg, a (vehicle acceleration) = 0.5 m / s2, μ (friction coefficient) = 0.04.

Ffr (sliding friction force) = μ * m * g (g – acceleration due to gravity (g = 10 m / s2)).

Formula: ma = F – μ * m * g and F = ma + μ * m * g.

Calculation: F = 20,000 * 0.5 + 0.04 * 20,000 * 10 = 10,000 + 8,000 = 18,000 N or 18 kN.

Answer: The traction force that imparts acceleration to the vehicle is 18 kN.