The carbon content in the hydrocarbon is 85.71%, its nitrogen density is 2.5. Name all substances

The carbon content in the hydrocarbon is 85.71%, its nitrogen density is 2.5. Name all substances that satisfy the condition of the problem.

Let’s execute the solution in accordance with the condition of the problem:
1. Given: CxNu;
W (C) = 85.71%
D (N2) = 2.5;
M (N2) = 28 g / mol;
Define: molecular formulas.
2. Calculations by formulas:
M (CxHy) = M (N2) * D (N2) = 28 * 2.5 = 70 g / mol;
Y (C) = m / M = 85.71 / 12 = 7.14;
m (C) = Y * M = 7.14 * 12 = 85.71;
m (H) = 100 – 85.71 = 14.29;
Y (H) = m / M = 14.29 / 1 = 14.29.
3. Ratio:
X: Y = 7.14: 14.29 = 1: 2;
The simplest formula CH2 shows the possibility of two variants of general formulas.
CnH2n – cycloparaffins;
CnH2n + 2 – saturated hydrocarbons.
Molecular formulas: C5H10 – cyclopentane;
C5H10 – pentene.
Checking: M (C5H10) = 70 g / mol.
Answer: hydrocarbons: C5H10 – cyclopentane, C5H10 – pentene.