The cart from the state of rest passed 6.25m with an acceleration of 0.32m / s².

The cart from the state of rest passed 6.25m with an acceleration of 0.32m / s². Determine the final speed of the cart during its movement.

Initial data: V0 (initial speed of the cart) = 0 m / s (the cart was moving from a state of rest); S (distance traveled) = 6.25 m; a (trolley acceleration) = 0.32 m / s2.

1) Determine the final speed of the cart: S = V ^ 2 / 2a, whence V = √ (2a * S) = √ (2 * 0.32 * 6.25) = 2 m / s.

2) Let’s calculate the time of movement of the cart: V = a * t, whence t = V / a = 2 / 0.32 = 6.25 s.

Answer: The cart from a state of rest accelerated to a speed of 4 m / s in 6.25 s.



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