The cart moves from a state of rest along an inclined railroad and point A to point B, What is the speed of the cart at point B

The cart moves from a state of rest along an inclined railroad and point A to point B, What is the speed of the cart at point B, if point A is at an altitude of 100m from the Earth, and point B is at an altitude of 60m.

To find the speed of a given trolley at point B, we will use the equality (the law of conservation of energy): EpA = EpB + EkB and m * g * hA = m * g * hB + m * V ^ 2/2, whence we express: V = √ (2 * (g * hA – g * hB)).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); hA – height of point A (hA = 100 m); hB – height of point B (hB = 60 m).

Let’s calculate: V = √ (2 * (g * hA – g * hB)) = √ (2 * (10 * 100 – 10 * 60)) = 28.28 m / s.

Answer: At point B, the speed of the given trolley will be 28.8 m / s.