The cart with sand is rolling at a speed of 1 m / s . Along a horizontal path without friction.

| March 7, 2021 | education

The cart with sand is rolling at a speed of 1 m / s . Along a horizontal path without friction. A ball weighing 2 kg flies towards the cart at a horizontal speed of 7 m / s. The ball after falling into the sand gets stuck in it. What is the modulus of speed at which the cart will roll after a collision with a ball?

To find the speed of the considered cart with sand, we will use the equality: msh * Vsh – mt * Vt = (msh + mt) * V, whence we express: V = (msh * Vsh – mt * Vt) / (msh + mt).

Variables: msh – ball mass (msh = 2 kg); Vsh – ball flight speed (Vsh = 7 m / s); mt is the mass of the cart with sand (mt = 10 kg); Vt is the initial speed of the carriage (Vt = 1 m / s).

Calculation: V = (2 * 7 – 10 * 1) / (2 + 10) = 0.33 (3) m / s.

Answer: After the ball hits, the cart with sand will roll at a speed of 0.33 (3) m / s.



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