The catalytic oxidation of acetaldehyde with oxygen gave acetic acid, the yield of which was 75%

| June 10, 2021 | education

The catalytic oxidation of acetaldehyde with oxygen gave acetic acid, the yield of which was 75%. This acid reacted with excess sodium carbonate. Gas evolved, forming an acidic salt with a mass of 5.04 g with sodium hydroxide. Determine the volume of oxygen (under normal conditions) reacted with the aldehyde.

2 CH3COOH + O2 = 2CH3COOH.

2СН3СООН + Na2CO3 = 2 CH3COONa + H2O + CO2

NaOH + CO2 = NaHCO3.

M (NaHCO3) = 84 g / mol.

n = 5.04 g: 84 g / mol = 0.06 mol.

0.06 mol – 75%,

x mol – 100%.

x = (0.06 mol × 100%): 75% = 0.08 mol.

n (NaHCO3) = n (CO2) = 0.08 mol.

n (CH3COOH) = 2n (CO2) = 0.08 × 2 = 0.16 mol.

n (O2) = ½ n (CH3COOH) = 0.16: 2 = 0.08 mol.

Find the volume of O2.

V = n Vn, where Vn is the molar volume of gas equal to 22.4 l / mol.

V = 0.08 mol × 22.4 L / mol = 1.792 L.

Answer: 1,792 L



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