The center angle AOB rests on the chord AB so that the angle OAB is 60 °.

The center angle AOB rests on the chord AB so that the angle OAB is 60 °. Find the length of the chord AB if the radius of the circle is 8.

Let’s draw from the point O, the center of the circle, the segments OA and OB, to the edges of the chord. The AOB triangle is isosceles since ОА = ОВ = R = 8 cm.

Since the central angle OAB resting on the chord AB is 60, the triangle AOB is equilateral, and therefore AB = R = 8 cm.

Answer: The chord length is 8 cm.