The center of the circle circumscribed about triangle ABC lies on side AB. Find the ABC angle if the BAC angle is 75 °.

Since, by condition, the center of the circle lies on the side AB of the triangle, AB is the diameter of the circumscribed circle.

The ACB angle is 90, since it is based on the diameter of the circle.

Then the angle ABC = 180 – BAC – ACB = 180 – 75 – 90 = 15.

Answer: Angle ABC = 15.



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