The central angle AOB, equal to 60 degrees, rests on a chord of length 4. Find the radius of the circle.

Let’s construct the radii ОА and ОВ.

In triangle AOB OB = OA = R cm, then triangle AOB is isosceles.

The central angle AOB is the inner angle of the triangle AOB, then in an isosceles triangle one of the acute angles is 60, then the triangle AOB is equilateral.

ОА = ОВ = AB = R = 4 cm.

Answer: The radius of the circle is 4 cm.



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