The centripetal acceleration of a body moving in a circle with a radius of 9 m at a constant speed
| August 16, 2021 | education
The centripetal acceleration of a body moving in a circle with a radius of 9 m at a constant speed is 4 m / s ^ 2. The period of revolution is.
Task data: R (radius of the circle) = 9 m; an (centripetal acceleration of a moving body) = 4 m / s2.
The period of revolution of a given moving body is expressed from the formula: an = V ^ 2 / R = (2 * Π * R / T) ^ 2 / R = 4 * Π ^ 2 * R ^ 2 / (R * T ^ 2) = 4 * Π ^ 2 * R / T ^ 2, whence T = √ (4 * Π ^ 2 * R / an).
Let’s perform the calculation: T = √ (4 * 3.14 ^ 2 * 9/4) = 9.42 s.
Answer: This moving body has an orbital period of 9.42 s.
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