The chemical amount of carbon dioxide released as a result of the reaction CaCO3 = CaO + CO2 is 0.5 mol.

The chemical amount of carbon dioxide released as a result of the reaction CaCO3 = CaO + CO2 is 0.5 mol. The mass (g) of calcium carbonate taken for decomposition is …

Given:
n (CO2) = 0.5 mol

To find:
m (CaCO3) -?

Decision:
1) Write the equation of a chemical reaction:
CaCO3 => CaO + CO2 ↑;
2) Calculate the molar mass of CaCO3:
M (CaCO3) = Mr (CaCO3) = Ar (Ca) * N (Ca) + Ar (C) * N (C) + Ar (O) * N (O) = 40 * 1 + 12 * 1 + 16 * 3 = 100 g / mol;
3) Determine the amount of CaCO3 substance (taking into account the coefficients in the reaction equation):
n (CaCO3) = n (CO2) = 0.5 mol;
5) Calculate the mass of CaCO3:
m (CaCO3) = n (CaCO3) * M (CaCO3) = 0.5 * 100 = 50 g.

Answer: The mass of CaCO3 is 50 g.