The child is swinging on a swing. In one minute, he made 15 vibrations, the amplitude of which is equal to one meter.

The child is swinging on a swing. In one minute, he made 15 vibrations, the amplitude of which is equal to one meter. Find the period of oscillation and the path of the child in four periods.

To find the period of oscillation of the child on the swing and the path traveled by him, we use the formulas: T = t / n and S = n1 * 4A.

Variables: t (duration of the child’s swing on the swing) = 1 min = 60 s; n is the number of swing vibrations (n = 15 swings); A – amplitude (A = 1 m); n1 is the considered number of oscillations (n1 = 4 oscillations).

Calculation: a) Period of oscillation of the child: T = t / n = 60/15 = 4 s.

b) The path covered by the child: S = n1 * 4A = 4 * 4 * 1 = 16 m.

Answer: The period of oscillation of the child is 4 s, the path for four periods is 16 m.