The chord AB of the circle with center O is equal to the radius of this circle. Find AOB.

From point O, the center of the circle, draw segments OA and OB equal to the radius of the circle.

By condition, the length of the radius of the circle is equal to the length of the chord AB, then the triangle AOB is equilateral.

In an equilateral triangle, all internal angles are 60, then the AOB angle is 60.

Answer: The value of the angle AOB is 60.

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