The chord AB subtracts the circular arc at 141 (degrees). The tangents to the circle drawn at points A

The chord AB subtracts the circular arc at 141 (degrees). The tangents to the circle drawn at points A and B will intersect at point O. Find the angle AOB

From the center of the circle, point C, draw the radii to the points of tangency A and B.

By the property of the tangent, the radii CA and СВ are perpendicular to the tangents ОА and ОВ, then the angles ОВС = ОАС = 90.

In the quadrangle ОАСВ, the sum of internal angles is 3600, then the angle АВ = (360 – ОВС – ОАС – АСВ) = (360 – 90 – 90 – 141) = 39.

Answer: The value of the angle AOB is 39.