The chord ab, the longitude of which is 30 cm, is divided by the point My in relativity 2: 1.

The chord ab, the longitude of which is 30 cm, is divided by the point My in relativity 2: 1. The distance from the point to the center of the circle is exactly 12 cm, find the angle AB.

Point M divides the chord AB in a ratio of 2/1.

Then AM = AB / 3 = 30/3 = 10 cm.

BM = 2 * AB / 3 = 2 * 30/3 = 20 cm.

The height OH divides the chord AB in half, then AH = BH = AB / 2 = 30/2 = 15 cm.

The length of the segment МН = ВМ – ВН = 20 – 15 = 5 cm.

In the right-angled triangle MHO, we determine the length of the leg OH.

OH ^ 2 = OM ^ 2 – MH ^ 2 = 144 – 25 = 119.

OH = √119 cm.

In a right-angled triangle, OBN tgB = OH / BH = √119 / 15 = 0.727.

Angle ABO = arctan 0.727 ≈ 360.

Answer: The ABO angle is 360.