The chord of the circle is 5 m and contracts an arc of 60 degrees. Find the length of a circle and arc.

From the center O of the circle, construct the radii OA and OB to the ends of the chord.

The degree measure of the arc AB, according to the condition, is equal to 60, then the central angle AOB is equal to the degree measure of the arc AB, the angle AOB = 60.

Since in the triangle AOB, AO = OB = R, and the angle AOB = 60, then triangle AOB is isosceles, and OA = OB = R = 5 m.

Determine the length of the circle.

Lokr = 2 * n * R = 2 * n * 5 = 10 * n m.

Let us determine the length of the smaller arc AB.

Lav = n * R * 60/180 = n * 5 * 60/180 = n * 5/3.

Answer: The length of the arc is 5 * n / 3 m, the circumference is 10 * n m.