The chord of the circle is 6√2 dm and contracts the arc at 90 degrees. Find the circumference and arc length.

The chord AB contracts the arc at 90, then the chord AB is the side of the square inscribed in the circle.

From a right-angled isosceles triangle, in which the angle AOB = BOA = 45, we define the leg AO, which is the radius of the circle.

AO = AB * Sin450 = 6 * √ 2 * √ 2/2 = 6 cm.

Determine the length of the circle.

L = 2 * n * AO = n * 2 * 6 = 12 * n.

Since the arc subtends angle 90, its length is equal to a quarter of the circumference (90/360).

Arc AB = L / 4 = 12 * p / 4 = 3 * p.

Answer: The circumference is 12 * p, the length of the arc is 3 * p.



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