The chords of the circle AB and CD intersect. Find the angle BAD, if angle ACD = 40, angle ADB = 60.

The internal angle ACD rests on the arc AD, then the degree measure of the arc AD = 2 * ACD = 2 * 40 = 80.

The internal angle ABD also rests on the arc AD, therefore, the angle ABD = ACD = 40.

Consider a triangle ABD.

Since the sum of the inner angles of the triangle is 180, the angle BAD = 180 – ABD – ADB = 180 – 40 – 60 = 80.

Answer: The value of the angle BAD is 80.



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