The circle includes three resistors with resistances R1 = 100 Ohm, R2 = 0.2 kOhm, R3 = 0.3 kOhm, as shown in the figure.

| February 12, 2021 | education

The circle includes three resistors with resistances R1 = 100 Ohm, R2 = 0.2 kOhm, R3 = 0.3 kOhm, as shown in the figure. Determine the total resistance of the circuit, the total voltage and amperage across the second resistor if the total amperage is 6A.

Determine the total resistance of the circuit if 3 resistors R1 = 100 Ohm, R2 = 0.2 kOhm, R3 = 0.3 kOhm are connected in series:
Ro = R1 + R2 + R3 = 100 + 0.2 * 1000 + 0.3 * 1000 = 100 + 200 + 300 = 600 Ohm.
Find the total voltage of the circuit if the current is 6 A:
U = I * Ro = 6 * 600 = 3600 V.
The current at the second resistor R2 is 6A, since the resistors are connected in series, and the current is equal for all resistors.
Answer: the total voltage of the circuit is 3600 V, the current at the second resistor R2 is 6 A.



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