# The circuit consists of inductance and capacitance connected in series. Determine the capacitance

July 29, 2021 | education

| **The circuit consists of inductance and capacitance connected in series. Determine the capacitance at resonance of voltages for an alternating current with a frequency of 500 kHz, if the inductance of the circuit is 0.725 mg.**

To calculate the value of the capacitance in a given circuit at voltage resonance, we will use the formula: Cut = 1 / (ω ^ 2 * L) = 1 / ((2 * Π * ν) ^ 2 * L).

Variable values: ν – AC frequency (ν = 500 kHz = 500 * 10 ^ 3 Hz); L is the inductance of the circuit (L = 0.725 mH = 0.725 * 10 ^ -3 H).

Calculation: Slice = 1 / ((2 * Π * ν) ^ 2 * L) = 1 / ((2 * 3.14 * 500 * 10 ^ 3) ^ 2 * 0.725 * 10 ^ -3) = 1.4 * 10 ^ -10 = 140 pF.

Answer: The capacitance in a given circuit at voltage resonance is 140 pF.

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