# The circuit consists of inductance and capacitance connected in series. Determine the capacitance

The circuit consists of inductance and capacitance connected in series. Determine the capacitance at resonance of voltages for an alternating current with a frequency of 500 kHz, if the inductance of the circuit is 0.725 mg.

To calculate the value of the capacitance in a given circuit at voltage resonance, we will use the formula: Cut = 1 / (ω ^ 2 * L) = 1 / ((2 * Π * ν) ^ 2 * L).

Variable values: ν – AC frequency (ν = 500 kHz = 500 * 10 ^ 3 Hz); L is the inductance of the circuit (L = 0.725 mH = 0.725 * 10 ^ -3 H).

Calculation: Slice = 1 / ((2 * Π * ν) ^ 2 * L) = 1 / ((2 * 3.14 * 500 * 10 ^ 3) ^ 2 * 0.725 * 10 ^ -3) = 1.4 * 10 ^ -10 = 140 pF.

Answer: The capacitance in a given circuit at voltage resonance is 140 pF. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.