Calculate the mass of the precipitate obtained by merging solutions containing 1 mol of copper (II)

Calculate the mass of the precipitate obtained by merging solutions containing 1 mol of copper (II) chloride and 0.408 mol of sodium hydroxide.

1. Let’s write down the equation of the proceeding reaction:

CuCl2 + 2NaOH = Cu (OH) 2 ↓ + 2NaCl;

2.From these quantities, we determine what quantities of sediment can be obtained:

n (Cu (OH) 2) = n (CuCl2) = 1 mol;

n (Cu (OH) 2) = n (NaOH): 2 = 0.408: 2 = 0.204 mol;

3.Using the smallest value of the chemical amount of the sediment, we find its mass:

m (Cu (OH) 2) = n (Cu (OH) 2) * M (Cu (OH) 2);

M (Cu (OH) 2) = 64 + 2 * 16 + 2 * 1 = 98 g / mol;

m (Cu (OH) 2) = 0.204 * 98 = 19.992 g.

Answer: 19.992 g.