The circumference of the front wheel of the carriage is 2.8 m and the rear wheel is 3.5 m.

The circumference of the front wheel of the carriage is 2.8 m and the rear wheel is 3.5 m. What distance will the carriage travel if the front wheel has made 50 revolutions more than the rear wheel?

Let’s write down the number of revolutions that the rear wheel has made as an unknown number x.

Since the front wheel has made 50 more revolutions, it has made: (x + 50) revolutions.

Since the distance traveled by the front and rear wheels is the same, we get equality:

2.8 * (x + 50) = 3.5 * x.

2.8 * x + 140 = 3.5 * x.

140 = 3.5 * x – 2.8 * x.

140 = 0.7 * x.

x = 140 / 0.7 = 200 revolutions (made the rear wheel).

We find the distance.

We multiply the number of revolutions by the circumference.

200 * 3.5 = 700 meters.

Answer: 700 m.