The coefficient of elasticity of the rubber cord is 1kN / m. Determine the potential energy of the cord when its elongation is 6cm.
| December 1, 2020 | education
In given it is said that we have a coefficient of elasticity k = 1kN / m,
And the elongation of the cord is X = 6 cm, we translate the values into the SI system, k = 1 kN / m = 1000 N / m, and X = 6cm = 0.06 m, and then we solve by the formula E = kX ^ 2/2, E = 1000 N / m * (0.06 m) ^ 2/2 = 1.8 J
Answer: E = 1.8 J
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