The coefficient of friction of the sled runners on the snow is 0.2

The coefficient of friction of the sled runners on the snow is 0.2. What force should a boy apply to pull the sled evenly if its weight is 48 kg.

μ = 0.2.
g = 9.8 m / s ^ 2.
m = 48 kg.
F -?
According to Newton’s 1 law, a body can move uniformly rectilinearly when the action of forces on it is compensated: F = Ftr.
Ftr = μ * N, where μ is the coefficient of friction, N is the reaction force of the support.
According to Newton’s 3 law, the reaction force of the support N is equal to the force with which the body is pressed to the ground m * g.
N = m * g.
F = μ * m * g.
F = 0.2 * 48 kg * 9.8 m / s ^ 2 = 94.08 N.
Answer: the boy must apply force F = 94.08 N.