The coin is thrown three times, find the probability that the coat of arms will fall out 1 time.
| June 11, 2021 | education
We use combinatorics.
Number of possible outcomes:
Number of placements with repetitions
n = s ^ k = 2 ^ 3 = 8
Number of Favorable Outcomes:
Choice without return and without regard to order
m = С (k, n) = n! / (k! * (n – k)!) = C (1, 3) = 3! / (2! * 1!) = 6/2 = 3
Ultimate probability
P = m / n = 3/8 = 0.375 = 37.5%
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