The combustion of 1 g of metal requires 462 ml of oxygen, determine the equivalent and name of the metal.

The equivalent volume of oxygen VE (O2) is 22.4 / 4 = 5.6 liters, because the molecule consists of 2 divalent O2 atoms. According to the law of mass equivalents (volumes) of reacting substances, m1 and m2 are proportional to their molar masses (volumes): m1 / Me1 = m2 / Me2;
m (Me) / Me (Me) = m (O2) / Me (O2);
Since oxygen is in a gaseous state, we write:
m (Me) / Me (Me) = V (O2) / Ve (O2);
1 / Meq. (Me) = 0.462 / 5.6;
Meq. (Me) = 12.
The molar mass of the metal equivalent is 12 g / mol.
There is no metal with such a molar mass. So we define the metal in this way: 12 * 2 = 24 – magnesium metal.



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