The combustion of 11.4 g of hydrocarbon produced 35.2 g of carbon monoxide (IV) and 16.2 kg of water vapor.

The combustion of 11.4 g of hydrocarbon produced 35.2 g of carbon monoxide (IV) and 16.2 kg of water vapor. The relative molecular weight of the islands 112. Set the molecular formula and indicate whether this hydrocarbon belongs to the limiting ones.

CH + O2 = CO2 + H2OC + O2 = CO₂m (C) = 12 * 35.2 / 44 = 9.6
gr2H2 + O2 = 2H2Om (H) = 4 * 16.2 / 36 = 1.8n (C): n (H) = 9.6 / 12: 1.8 / 1 = 0.8 / 0.8: 1.8 / 0.8 = 1: 2.25 * 4 = 4: 9
С8Н16