The combustion of hexane produced 11.2 liters of carbon dioxide. What is the mass of the burned hydrocarbon?

Given:
V (CO2) = 11.2 l.
interaction of C6H14 with O2;
Find: m (C6H14) -?
Decision:
1) Let’s write the reaction equation:
2C6H14 + 19O2 = 12CO2 + 14H2O + Q;
From the reaction – 12 mol of CO2 is consumed per 2 mol of C6H14;
2) Find v (CO2), v (CO2) = 11.2 l / 22.4 l / mol = 0.5 mol.
Since v (C6H14): v (CO2) = 2: 12, then v (C6H14) = 12 * 0.5 / 2 = 3 mol;
4) M (C6H14) = 12 * 6 + 14 = 72 + 14 = 86 g / mol.
m (C6H14) = 86 g / mol * 3 mol = 258 g.
Answer: The formation of 11.2 liters of carbon dioxide is possible with the combustion of 258 grams of C6H14.