The combustion of phosphorus produced 284 grams of P2O5. How many grams of oxygen entered into the reaction?

The synthesis reaction of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. During the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus oxide weighing 284 grams.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

N P2 O5 = 284/142 = 2 mol;

To synthesize such an amount of oxide, you need to take 2/2 x 5 = 5 mol of oxygen.

Let’s calculate its weight.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 5 x 32 = 160 grams;