The composition of stainless steel contains 12.1% nickel find the mass of nickel in a steel ingot weighing 5 kg.

These tasks: msl – the mass of the ingot (msl = 5 kg); µn – percentage of nickel content (µn = 12.1%).

To find out the mass of nickel in the specified stainless steel ingot, we use the ratio: mn / µn = msl / 100%, from where we express: mn = µn * msl / 100%.

Let’s perform the calculation: mn = µn * msl / 100% = 12.1% * 5/100% = 0.605 kg.

Answer: The specified stainless steel ingot contains 0.605 kg of nickel.



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