The conveyor lifts 200 kg of sand onto a car in 1 s. The length of the conveyor belt is 3 m, its angle

| April 19, 2021 | education

The conveyor lifts 200 kg of sand onto a car in 1 s. The length of the conveyor belt is 3 m, its angle of inclination to the horizon is 30 degrees. The efficiency of the conveyor is 0.85. Find the power supplied by its electric motor.

To find the power value of the electric motor of the used conveyor, we apply the formula: η = Np / Nt = (A / t) / Nt = m * g * h / (t * NT) = m * g * l * sinα / (t * Nt), whence we express: NT = m * g * l * sinα / (t * η).

Constants and variables: m – mass of the lifted sand (m = 200 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); l is the length of the conveyor belt (l = 3 m); α – angle of inclination of the tape (α = 30º); t is the operating time (t = 1 s); η – conveyor efficiency (η = 0.85).

Let’s perform the calculation: NT = m * g * l * sinα / (t * η) = 200 * 9.8 * 3 * sin 30º / (1 * 0.85) = 3459 W ≈ 3.5 kW.

Answer: The power of the conveyor used is 3.5 kW.



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