The conveyor lifts 30 m3 of sand to a height of 6 m for 1 hour. Calculate the engine power

The conveyor lifts 30 m3 of sand to a height of 6 m for 1 hour. Calculate the engine power required for this work. The density of the sand is 1500kg / m3.

To find the required engine power of the conveyor under consideration, we apply the formula: N = A / t = m * g * h / t = ρp * V * g * h / t.

Variables and constants: ρп – density of the lifted sand (by condition ρп = 1500 kg / m3); V is the volume of sand (V = 30 m3); g – acceleration due to gravity (g ≈ 9.8 m / s2); h – height (h = 6 m); t is the operating time of the conveyor (t = 1 h = 3600 s).

Calculation: N = ρp * V * g * h / t = 1500 * 30 * 9.8 * 6/3600 = 735 W.

Answer: The required engine power of the conveyor in question is 735 W.