The conveyor lifts a 300kg load to a height of 16m in 2min. Determine the amperage

| September 6, 2021 | education

The conveyor lifts a 300kg load to a height of 16m in 2min. Determine the amperage in the conveyor motor if the mains voltage is 380V and the conveyor efficiency is 60%.

To find the value of the current in the electric motor of the used conveyor, we apply the formula: η = Ap / Qz = m * g * h / (U * I * t), whence I = m * g * h / (U * t * η).

Constants and variables: m is the mass of the cargo lifted by the conveyor (m = 300 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); h – lifting height (h = 16 m); U – mains voltage (U = 380 V); t – operating time (t = 2 min = 120 s); η – conveyor efficiency (η = 60% = 0.6).

Calculation: I = m * g * h / (U * t * η) = 300 * 9.8 * 16 / (380 * 120 * 0.6) = 1.72 A.

Answer: The current in the electric motor of the used conveyor is 1.72 A.



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