The coordinate of the ball of the spring pendulum changes from x = 8cm to x = -8cm. What is the vibration amplitude?

Given: X = 8 cm to X1 = – 8 cm

Find: A -?


The vibration amplitude is the modulus of maximum displacement from the equilibrium position. The vibration amplitude will be equal to the length of the OX segment. For greater accuracy, the length of the segment XX1 can be divided by 2, since the segment XX1 corresponds to two amplitudes.

Since | OH | = 8 cm, therefore, the vibration amplitude A = 8 cm = 0.08 m


A = | XX1 | / 2 = 16 cm / 2 = 8 cm = 0.08 m.

Answer: A = 8 cm.

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