The cork lifebuoy has a mass of 12 kg. What is the mass of the weight that is supported by

The cork lifebuoy has a mass of 12 kg. What is the mass of the weight that is supported by this circle if the circle is half immersed in water?

Given: m (mass of the cork circle) = 12 kg; V1 (volume of the immersed part of the circle) = 0.5V.

Constants: ρp (plug density) = 240 kg / m3; ρw (water density) = 1000 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

1) Determine the volume of the circle: V = mk / ρp = 12/240 = 0.05 m3.

2) Find the lifting force: Fd = Fa – P = ρw * g * V1 – m * g = 1000 * 10 * 0.5 * 0.05 – 12 * 10 = 250 – 120 = 130 N.

3) We calculate the mass of the cargo: m = Fpod / g = 130/10 = 13 kg.

Answer: The circle will be able to support a load weighing 13 kg.



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