The corner of the isosceles triangle is 60 degrees greater than the base angle. Find the corners of the base of the triangle.

In order to find the angles at the base of an isosceles triangle, we will compose and solve an equation.

So, in the first step, let’s recall the properties of the angles at the base of an isosceles triangle and the theorem on the sum of the angles of a triangle.

So, the angles at the base of an isosceles triangle are equal to each other. And the sum of the angles of a triangle is 180 °.

Let’s denote by x ° the angle at the base, then (x + 60) ° the angle at the top.

x + x + (x + 60) = 180;

x + x + x + 60 = 180;

3x = 180 – 60;

3x = 120;

x = 120: 3

x = 40 ° angle at the base.