The corresponding legs of two similar right-angled triangles are 5 dm and 10 dm

The corresponding legs of two similar right-angled triangles are 5 dm and 10 dm. Find the hypotenuse of the larger triangle if the hypotenuse of the smaller one is 7 dm.

To solve this problem, we draw up an equality in which the leg of the first triangle a1 refers to the leg of the second triangle a2 in the same way as the hypotenuse of the first triangle c1 refers to the hypotenuse of the second triangle c2.

In this case, we get:

5/10 = 7 / s2.

1/2 = 7 / s2.

Find the unknown value of the hypotenuse c2.

c2 = 7 / 1/2 = 7 * 2 = 14 cm.

Answer:

The hypotenuse of the second triangle is 14 cm.