The cosine of one of the acute corners of a right-angled triangle is 0.6. What is the other acute angle?

Let the first acute angle given in the task be equal to α, then cos α = 0.6.

Let’s designate the second acute angle in the triangle β, then it will be equal to: β = 90 ° – a.

Then sin β = sin (90 ° – α) = cosα = 0.6. This means the angle β will be equal to: arcsin 0.6 ≈ 0.64 °.



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